An experiment consists of randomly selecting a marble from a bag, keeping it, and then selecting another marble. The bag contains 4 blue marbles, 3 green marbles, 7 red marbles, and 1 yellow marble. What is the probability of selecting a red marble and then a blue marble? Question 3 options: 20% 13.33% 10% 16.66%

Answer:13.33% Step-by-step explanation:First we need to find the total number of marbles 4 blue marbles+ 3 green marbles+ 7 red marbles+ 1 yellow marble= 15The probability of a red marble = number of red marbles over the total marblesP(red) = red/total = 7/15We keep the marble.  There are now 6 red marbles 4 blue marbles+ 3 green marbles+ 6 red marbles+ 1 yellow marble= 14We have 14 marbles in the bagThe probability of a blue marble = number of blue marbles over the total marblesP(blue) = blue/total = 4/14 = 2/7Then we multiply the probabilities togetherP(red,blue0 = 7/15 * 2/7 = 2/15 =.13333333 = 13.33%