Q:

Define the points ​P(negative 4−4​,negative 2−2​) and ​Q(33​,negative 4−4​). Carry out the following calculation. Find two vectors parallel to ModifyingAbove QP with right arrowQP with length 22.

Accepted Solution

A:
Answer:The required vectors are [tex]u=<-\frac{14}{\sqrt{53}},\frac{4}{\sqrt{53}}>[/tex] and [tex]v=<\frac{14}{\sqrt{53}},-\frac{4}{\sqrt{53}}>[/tex].Step-by-step explanation:Given information: P(-4,-2) and Q(3,-4).We need to find the two vectors parallel to [tex]\overrightarrow {QP}[/tex] with length 2.If [tex]A(x_1,y_1)[/tex] and [tex]B(x_2,y_2)[/tex], then[tex]\overrightarrow {AB}=<x_2-x_1,y_2-y_1>[/tex][tex]|\overrightarrow {AB}|=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]Using the above formula we getvector QP is,[tex]\overrightarrow {QP}=<-4-3,-2-(-4)>=<-7,2>[/tex]Magnitude of vertor QP is,[tex]|\overrightarrow {QP}|=\sqrt{(-4-3)^2+(-2-(-4))^2}[/tex][tex]|\overrightarrow {QP}|=\sqrt{(-7)^2+(2)^2}[/tex][tex]|\overrightarrow {QP}|=\sqrt{49+4}[/tex][tex]|\overrightarrow {QP}|=\sqrt{53}[/tex]Using vector is[tex]\widehat {QP}=\frac{\overline {QP}}{|\overline {QP}|}[/tex][tex]\widehat {QP}=\frac{1}{\sqrt{53}}<-7,2>[/tex][tex]w=\widehat {QP}=\frac{1}{\sqrt{53}}<-\frac{7}{\sqrt{53}},\frac{2}{\sqrt{53}}>[/tex]Multiply vector w by 2 to get a parallel vector parallel of QP in same direction.[tex]u=2w=<-\frac{14}{\sqrt{53}},\frac{4}{\sqrt{53}}>[/tex]Multiply vector w by -2 to get a parallel vector parallel of QP in opposite direction.[tex]v=-2w=<\frac{14}{\sqrt{53}},-\frac{4}{\sqrt{53}}>[/tex]Therefore the required vectors are [tex]u=<-\frac{14}{\sqrt{53}},\frac{4}{\sqrt{53}}>[/tex] and [tex]v=<\frac{14}{\sqrt{53}},-\frac{4}{\sqrt{53}}>[/tex].