On a coordinate plane, a straight red line with a negative slope, labeled g of x, crosses the y-axis at (0, negative 7). A straight blue line with a positive slope, labeled f of x, crosses the x-axis at (negative 1, 0) and the y-axis at (0, 2). Both lines intersect at (negative 3, negative 4). Which statement is true regarding the functions on the graph? f(–3) = g(–4) f(–4) = g(–3) f(–3) = g(–3) f(–4) = g(–4)

Answer:[tex]f(-3)=g(-3)[/tex]Step-by-step explanation:The graph shows two linear functions that intersect at (-3,-4).The blue line is f(x).At the point of intersection:[tex]f(-3)=-4[/tex]....eqn1The blue line is g(x).At the point of intersection [tex]g(-3)=-4[/tex]....eqn2Equating both equations we get:[tex]f(-3)=g(-3)[/tex]The statement that is true regarding the two functions is that:[tex]f(-3)=g(-3)[/tex]